NCERT Solutions for Class 9th Maths Chapter 8 Think and Reflect — Introduction to Sequences

Book page 174 Updated on2026-09-08

Q1.
Can you describe the pattern in each of the above sequences? Can you predict the next few numbers in these sequences?
Answer

Each of the four sequences is described by what happens from one term to the next, and that alone fixes every later term.

SequencePattern in the gapsNext three termsRule for the nth term
1, 2, 3, 4, 5, 6, …add 1 each time7, 8, 9tn = n
1, 3, 5, 7, 9, 11, …add 2 each time13, 15, 17tn = 2n – 1
1, 3, 6, 10, 15, 21, …gaps are 2, 3, 4, 5, 6 — they grow by 128, 36, 45tn = n(n + 1)/2
1, 4, 9, 16, 25, 36, …gaps are 3, 5, 7, 9, 11 — the odd numbers49, 64, 81tn = n2

Check the last two rows against the printed terms: 21 + 7 = 28, 28 + 8 = 36, 36 + 9 = 45; and 36 + 13 = 49, 49 + 15 = 64, 64 + 17 = 81. The gaps themselves form a sequence, and that is what makes prediction possible.

Why it happens: the triangular numbers are the running totals of 1, 2, 3, 4, …, so the gap between the (n – 1)th and the nth is exactly n. The square numbers are the running totals of 1, 3, 5, 7, …, so the gap there is the nth odd number, 2n – 1. In both cases you are not guessing — you are reading off a structure the sequence already has.
Check it yourself: 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28, and 1 + 3 + 5 + 7 + 9 + 11 + 13 = 49. The two lists of running totals really do give the triangular and square numbers.
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