NCERT Solutions for Class 9th Science Chapter 4 Bridging Science and Society — Kinematic equations

Book page 65 Updated on2026-09-08

Q1.
Can you now understand why it is important to maintain a safe distance from the vehicle moving ahead of your vehicle (Fig. 4.20) and how this distance needs to be adjusted given your initial velocity?
Answer

Yes. A vehicle cannot stop where the driver decides to stop — it stops where physics allows, and that place is set by u², not by u.

stopping distance = reaction distance + braking distance
= u tr + u² / (2|a|)   [the second term from v² = u² + 2as with v = 0]

Using the chapter's own braking figure of |a| = 4 m s⁻² and a reaction time tr = 1 s:

Initial velocity uReaction distance u trBraking distance u²/2|a|Total stopping distance
36 km h⁻¹ = 10 m s⁻¹10 m12.5 m22.5 m
54 km h⁻¹ = 15 m s⁻¹15 m28.1 m43.1 m
108 km h⁻¹ = 30 m s⁻¹30 m112.5 m142.5 m

Going from 54 to 108 km h⁻¹ doubles the speed but makes the stopping distance more than three times longer — because the braking part alone becomes four times longer.

Why it happens: during braking the vehicle loses kinetic energy at a roughly steady rate set by the friction the tyres can supply, and the speed enters that balance as a square. The reaction part is different in nature: it is a stretch of road covered at full speed with no braking at all, so it simply grows in proportion to u. This is why a fixed "keep 20 m behind" rule is useless — the safe gap must grow with speed, which is why drivers are taught a time gap (2–3 s) instead.
Did you know? Anything that lowers |a| — a wet or gravelly road, worn tyres, a heavily loaded truck — stretches the braking term inversely. Halve the grip and every braking distance in the table doubles. Vehicle-to-vehicle (V2V) technology, now being developed in India and elsewhere, attacks the other term instead: it lets the vehicle ahead warn you electronically, cutting the reaction time far below a human's.
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