NCERT Solutions for Class 9th Science Chapter 6 .7 Forces Acting on a System of Objects — In-text Questions

Book page 1116 Updated on2026-09-08

Q1.
But can we apply these laws to two or more objects connected together?
Answer

Yes. Two or more connected objects can be treated as a single system and Newton's laws applied to that system as a whole.

Forces inside the system (internal forces) — e.g. the tension T in the connecting string — need not be considered
Only forces from outside the system (external forces) matter — e.g. the applied force F

a = F ÷ (mass of the system) = F ÷ (m1 + m2) … Eq. 6.4
Why internal forces can be ignored: by Newton's third law they always come in equal and opposite pairs — the string pulls Box 1 backwards and Box 2 forwards with the same T. Added over the whole system, each pair cancels, so they cannot change the motion of the system as a whole. The two boxes then accelerate exactly like one object of mass m1 + m2.
Tip: your own body is a system too. While walking, your arms and legs move in a complicated way, yet your overall motion can be studied by treating your body as a single object. Science often becomes simpler when we stop looking at parts and start looking at the whole.
Q2.
How can we find the acceleration of each box?
Answer

Treat the two boxes and the string as one system. Both boxes are tied together, so both have the same acceleration:

External force on the system = F (tension T is internal)
Mass of the system = m1 + m2

a = F ÷ (m1 + m2) … Eq. 6.4
This single value of a is the acceleration of both Box 1 and Box 2

Worked example. Let m1 = 3 kg, m2 = 2 kg and F = 10 N on a frictionless surface.

a = 10 N ÷ (3 kg + 2 kg) = 10 N ÷ 5 kg = 2 m s–2

Tension, from Box 2 alone: T = m2a = 2 kg × 2 m s–2 = 4 N
Check with Box 1: F – T = 10 N – 4 N = 6 N = m1a = 3 kg × 2 m s–2
Box 2 Box 1 string F T (internal pair — cancels) a = F ÷ (m₁ + m₂), the same for both boxes
The two tensions form an equal and opposite internal pair, so only F acts on the system from outside.
Tip: the other external forces — the total weight (m1 + m2)g downwards and the total normal force (N1 + N2) upwards — balance each other, so they do not enter the horizontal equation.
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