First identify the metal. Its valence shell is the M shell and it holds two electrons, so the configuration is 2, 8, 2 — that is Z = 12, magnesium.
(i) Formula — MO (magnesium oxide, MgO)
M (2, 8, 2) → M²⁺ (2, 8) + 2 e⁻
O (2, 6) + 2 e⁻ → O²⁻ (2, 8)
Criss-cross the charges: M₂O₂, divide by 2 → MO
Charge check: (+2) + (−2) = 0 ✓
(ii) Type of bond — ionic. A metal with two valence electrons meets a non-metal that is two electrons short. Electrons are transferred, not shared, giving M²⁺ and O²⁻, which are then held together by electrostatic attraction.
(iii) Conductivity of its aqueous solution — it conducts, but only weakly. Whatever little of it dissolves goes into solution as free M²⁺ and O²⁻ (in practice OH⁻) ions, and mobile ions carry a current. But since the compound is only slightly soluble, the number of ions in the solution is small, so the bulb glows dimly rather than brightly.
Why it happens: conductivity depends on how many mobile ions there are per unit volume, not merely on whether the compound is ionic. The bond type decides whether ions can appear; the solubility decides how many do.
Did you know? A suspension of this same slightly soluble compound in water is sold as milk of magnesia and taken to relieve acidity — a use it has precisely because it dissolves so little.